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Fix source nonetype error
Just incase, wrap in a try/except because it's not important.
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1 changed files with 12 additions and 12 deletions
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@ -51,19 +51,19 @@ def sources():
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etree.SubElement(source, 'path', attrib={'pathversion': "1"}).text = "smb://"
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etree.SubElement(source, 'path', attrib={'pathversion': "1"}).text = "smb://"
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etree.SubElement(source, 'allowsharing').text = "true"
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etree.SubElement(source, 'allowsharing').text = "true"
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files = xml.find('files')
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try:
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files = xml.find('files') or etree.SubElement(xml, 'files')
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if files is None:
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for source in xml.findall('.//path'):
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files = etree.SubElement(xml, 'files')
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if source.text == 'http://kodi.emby.media':
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break
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for source in xml.findall('.//path'):
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else:
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if source.text == 'http://kodi.emby.media':
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source = etree.SubElement(files, 'source')
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break
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etree.SubElement(source, 'name').text = "kodi.emby.media"
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else:
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etree.SubElement(source, 'path', attrib={'pathversion': "1"}).text = "http://kodi.emby.media"
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source = etree.SubElement(files, 'source')
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etree.SubElement(source, 'allowsharing').text = "true"
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etree.SubElement(source, 'name').text = "kodi.emby.media"
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except Exception as error:
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etree.SubElement(source, 'path', attrib={'pathversion': "1"}).text = "http://kodi.emby.media"
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LOG.exception(error)
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etree.SubElement(source, 'allowsharing').text = "true"
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indent(xml)
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indent(xml)
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write_xml(etree.tostring(xml, 'UTF-8'), file)
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write_xml(etree.tostring(xml, 'UTF-8'), file)
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